8x^2-5=-12x

Solution for 8x^2-5=-12x equation:

8x^2-5=-12x

We move all terms to the left:

8x^2-5-(-12x)=0

We get rid of parentheses

8x^2+12x-5=0

a = 8; b = 12; c = -5;
Δ = b2-4ac
Δ = 122-4·8·(-5)
Δ = 304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{304}=\sqrt{16*19}=\sqrt{16}*\sqrt{19}=4\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{19}}{2*8}=\frac{-12-4\sqrt{19}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{19}}{2*8}=\frac{-12+4\sqrt{19}}{16}
$